This manuscript was published in edited form by European Journal of Physics

© 2017 European Physical Society

The Michelson-Morley experiment has been of paramount importance in the history of physics, paving the way for Einstein's theory of Relativity through its null-result when trying to detect the motion of the earth through the hypothetical 'luminiferous ether' by his interferometer device. First carried out in 1881 by Michelson, the experiment was repeated in 1887 with a more accurate apparatus by Michelson and Morley after Potier (1881) and Lorentz (1886) pointed out that Michelson ignored the aberration of the transverse beam, which halved the expected effect and thus rendered the original experiment not accurate enough. However, neither of these theoretical treatments ( nor any more recent publications in this respect like that of Feynman (also reproduced on Wikipedia) ) consistently evaluated the theory in terms of wave optics. They were instead a kind of hybrid wave-particle modes that assumed interference of the beams but otherwise treated their propagation and reflection like that of particles, assuming for instance right angle reflection in the interferometer frame and also an aberration effect. It is shown below that a correct application of classical wave optics in this sense would predict a quantitatively substantially different result.

## Theory

In contrast to Michelson's original theory and most educational texts we consider the problem from the outset in the reference frame of the interferometer (in which after all the observations are made). In this case, the only aspect of relevance here is the speed of light in a given direction depending on the relative velocity of the moving 'ether' (in which by assumption the speed of light is isotropic). Michelson assumed for his theory that the light is 100% dragged by the ether and has a constant speed c in the ether's reference frame regardless of the relative velocity of the light source. This was in principle an unfounded assumption and in fact would appear to contradict Fizeau's experiment (which was already well known at the time), since a 100% drag would require an infinite refraction index and thus, paradoxically, imply a zero propagation speed of light. The only justification for assuming a 100% drag would be to hypothesize that the luminiferous ether is a special medium that affects light differently to normal matter, and we shall use this assumption here for the sake of the argument).

### Aberration of Plane Waves

In order to obtain the correct optical paths of the light signal in the interferometer frame, we have to consider how the orientation of the wave front of a plane depends on the velocity of the ether medium. In the left part of the below illustration we have the wave front propagation upwards with speed c for the ether at rest (v=0)(4 positions are indicated). The right part shows the wave front for the ether moving with velocity v to the left. The two points A and B on the wave front move now on an inclined path, but the orientation of the wave front is unchanged. Since the normal to the wave front defines the direction of propagation of the wave, there is thus no aberration occurring here; the wave is still moving vertically upwards with speed c, and there is no change in the phase difference between any two points.

Fig.1 : Wave propagation for resting and moving ether

The speed of light in the interferometer frame is therefore**v**,**c**) is the component of the ether velocity vector along the direction of light propagation. If the two directions are co-aligned we have thus the usual relationship c_{i} = c±v , whereas for the two directions being orthogonal, we have c_{i} = c (this is what Michelson actually correctly assumed in his original theory, adding only later an aberration effect based on the opinions of Potier and Lorentz).

An importance consequence of Eq.(1) (which to the author's knowledge has not been addressed yet in the literature at all), is the fact that the speed and thus the wavelength of light in the interferometer frame is not isotropic, and thus the usual reflection law does not apply anymore. A light beam falling onto a mirror at a 45^{o} angle will in general not be reflected by 90^{o} (as assumed in the literature throughout) but will deviate from this by a certain amount, which in turn changes the optical path lengths. In the next section we will determine this deviation angle as a function of the ether speed and direction, and in the subsequent section we will work out the correct phase difference in the optical paths on this basis. In contrast to the usual theory, we assume the velocity vector to have an arbitrary direction in the optical plane of the instrument.

### Reflection Angle

In order to calculate the deviation angle, we have to consider the geometrical relationships as illustrated below (Fig.2). We assume the incident plane wave of width w1 going horizontally from left to right and hitting the mirror at 45^{o} (as shown above, this condition is independent of the ether velocity and can thus be considered as set).

Fig.2: Condition for beam reflection in reference frame of mirror (v=ether velocity)

According to (1), the wavelength of the light before reflection is (with**v** the velocity of the ether relative to the mirror and α the angle between **v** and the light beam direction)

The number of wavelengths in the length x_{1} (the path difference between the two sides of the incoming beam) is
^{o} angle)
### Phase Difference between Optical Paths

Taking the correct wavelengths in the optical paths and associated reflection angle (as derived in the previous) into account, the number of wavelengths in the longitudinal and 'transverse' optical paths between the semi-transparent 45^{o} mirror and the two reflecting mirrors are (see Fig.3 below)

Fig.3: Beam paths in reference frame of interferometer (v = relative velocity of medium)

(note that the additional paths to the optical plane (dashed red and blue in Fig. 3) are of the same length and have the same wavelength (as they are parallel), so there is no change in the phase difference through this).

In contrast, the corresponding equations for the original theory of Michelson and Morley (that is incorrectly assuming right angle reflection in the interferometer frame and aberration of the normal to the wave front between the interferometer and ether frame (see Sect.'Aberration of Plane Waves' above ) the corresponding equations are_{0}^{.}v^{2}/c^{2}

Fig.4: Variation of phase difference with varying ether velocity direction α ; red: Michelson-Morley theory; blue wave optics approach)

It is obvious that the two curves coincide only in two points, namely when the ether velocity is parallel to the 45^{o} mirror. In this case the phase difference is zero because the reflection is exactly at a right angle as per (10). The theory of Michelson and Morley incorrectly predicts zero phase difference also when the velocity vector is perpendicular to the mirror surface, as it neglects the deviation of the reflection angle from a right angle as per (10). Instead, the other two zero points are obtained from (17) occur at approximately 18.4^{o} and 198.4^{o}. Overall, the amplitude of the phase variation should be more than twice that assumed by Michelson and Morley, with the phase difference staying almost completely negative throughout due to the actual deviation from right-angle reflection for the transverse beam.
## Conclusion

It has been shown in the present treatment that a correct consideration of wavelengths in the optical paths of the Michelson interferometer would result in a substantially different result for the phase differences in the interferometer from that predicted by Michelson and Morley. Even though in the end it would not have made any difference for the outcome of the experiment, Michelson's theory as such was substantially flawed and therefore not suitable to draw any valid conclusions from the experimental result.. Educational texts covering the Michelson-Morley experiment should therefore be revised in this sense. Additionally, aspects covered on this page may also be of relevance for other experiments using Michelson-type interferometers.

Fig.1 : Wave propagation for resting and moving ether

The speed of light in the interferometer frame is therefore

(1) **c**_{i} = **c**+**v**^{.}cos(**v**,**c**)

An importance consequence of Eq.(1) (which to the author's knowledge has not been addressed yet in the literature at all), is the fact that the speed and thus the wavelength of light in the interferometer frame is not isotropic, and thus the usual reflection law does not apply anymore. A light beam falling onto a mirror at a 45

Fig.2: Condition for beam reflection in reference frame of mirror (v=ether velocity)

According to (1), the wavelength of the light before reflection is (with

(2) λ_{1} = (c -v^{.}cos(α))/f = λ_{0}^{.}(1 -v/c^{.}cos(α))

(3) λ_{2} = (c -v^{.}cos(90-α-θ))/f = λ_{0}^{.}(1 -v/c^{.}sin(α+θ))

The number of wavelengths in the length x

(4) n_{1} = x_{1}/λ_{1}

(5) n_{2} = x_{2}/λ_{2}

(6) n_{2} = n_{1}

(7) x_{1} = w_{1}

(8) x_{2} = w_{1}^{.}√2^{.}cos(π/4-θ)

(9) (cos(θ)+sin(θ)) / (1 -v/c^{.}sin(α+θ)) = 1/(1 -v/c^{.}cos(α))

(10) θ ≈ v/c^{.}(cos(α)-sin(α))

Fig.3: Beam paths in reference frame of interferometer (v = relative velocity of medium)

(11) N_{l} = L/λ_{0}/(1 -v/c^{.}cos(α)) + L/λ_{0}/(1 +v/c^{.}cos(α)) =

= 2L/λ_{0}/(1-v^{2}/c^{2}^{.}cos^{2}(α)) ≈

≈ 2L/λ_{0}^{.}(1+v^{2}/c^{2}^{.}cos^{2}(α))

(12) N_{t} = d/λ_{0}/(1 -v/c^{.}cos(π/2-α-θ)) + d/λ_{0}/(1 +v/c^{.}cos(π/2-α+θ)) =

= L/λ_{0}/cos(θ)/(1 -v/c^{.}sin(α+θ)) + L/λ_{0}/cos(θ)/(1 +v/c^{.}sin(α-θ)) ≈

≈ L/λ_{0}^{.}(1+θ^{2}/2) ^{.}(2+v/c^{.}(sin(α+θ)-sin(α-θ)) + v^{2}/c^{2}^{.}(sin^{2}(α+θ)+sin^{2}(α-θ)) ≈

≈ 2L/λ_{0}^{.}(1+v^{2}/c^{2}^{.}(3/2-sin(2α))

(note that the additional paths to the optical plane (dashed red and blue in Fig. 3) are of the same length and have the same wavelength (as they are parallel), so there is no change in the phase difference through this).

In contrast, the corresponding equations for the original theory of Michelson and Morley (that is incorrectly assuming right angle reflection in the interferometer frame and aberration of the normal to the wave front between the interferometer and ether frame (see Sect.'Aberration of Plane Waves' above ) the corresponding equations are

(13) N_{l}^{MM} ≈ 2L/λ_{0}^{.}(1+v^{2}/2c^{2}^{.}(1+cos(^{2}α))

(14) N_{t}^{MM} ≈ 2L/λ_{0}^{.}(1+v^{2}/2c^{2}^{.}(1+sin(^{2}α))

(15) c_{l}^{MM} = √ (c^{2}+v^{2} ∓2cv^{.}(cos(α∓v/c^{.}sin(α))

(16) c_{t}^{MM} = √ (c^{2}+v^{2} ∓2cv^{.}(sin(α±v/c^{.}cos(α))

(17) N_{l}-N_{t} ≈ 2L/λ_{0}^{.}v^{2}/c^{2}^{.}(cos^{2}(α)+sin(2α)-3/2)

(17) (N_{l}-N_{t})^{MM} ≈ 2L/λ_{0}^{.}v^{2}/2c^{2}^{.}cos(2α)

Fig.4: Variation of phase difference with varying ether velocity direction α ; red: Michelson-Morley theory; blue wave optics approach)

It is obvious that the two curves coincide only in two points, namely when the ether velocity is parallel to the 45

Thomas Smid (M.Sc. Physics, Ph.D. Astronomy)

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